The Math

It is not quite as stark as for Huckabee, but the math for Clinton to catch up and win is pretty bad.

How Many Delegates Does HRC Need To Win?
(Marc Ambinder, The Atlantic)

Let’s go to March 4. Let’s assume that Clinton wins Ohio by four points – 52 to 48, netting her roughly 5 extra delegates, and loses Texas 49 to 51, netting Obama three extra delegates, and loses Vermont, netting Obama three extra delegates, and winning Rhode Island by 6 points, netting herself an extra delegate. She ends that day with no additional delegates – she can blame Vermont.

Under the rosiest of scenarios, it’s hard to see her winning more than about 50 percent of the remaining earned delegates, even if she whips Obama in Pennsylvania and earns, say, 16 extra delegates, and drums him in Puerto Rico, where, even if she wins seventy percent of the delegates, she’s still, in essence, playing catch up.

If Clinton wins half of the remaining delegates – about 493 – and loses none – she still trails Obama by a net 50 or so earned delegates.

Now let’s run the scenario with Florida and Michigan’s delegates in play – the best iteration of that scenario, with both pledged and unpledged delegates seated and Clinton’s having earned fully 60% of or more of them. She’ll need at least 52.1% of remaining pledged delegates to surpass Obama.

Playing with the numbers a bit, here’s how she could – in theory – accomplish this.

If Florida and Michigan’s delegations are seated fully to her advantage, and if she wins in Ohio by 65% and wins in Texas by 65%, and all other percentages hold, she can win the nomination.

(via The Daily Dish)

She’s not going to take Ohio and Texas. Maybe not at all. Certainly not by those margins. And the superdelegates will NOT save her if Obama is way ahead on pledged delegates coming into the convention. And unless she comes into the convention already ahead, (or unless Obama is so far ahead it won’t matter) Florida and Michigan will not be seated.

She’s done.